[Basic Mathematics] 특수각에 대한 삼각함수 값

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특수각에 대한 삼각함수 값

 

• $ 0 $

$$ \sin 0 = 0 $$

$$ \cos 0 = 1 $$

$$ \tan 0 = 0 $$

$$ \csc 0 \text{   undefined} $$

$$ \sec 0 = 1 $$

$$ \cot 0 \text{   undefined} $$

• $ \dfrac{\pi}{6} = 30^\circ $

$$ \sin \dfrac{\pi}{6} = \dfrac{1}{2} $$

$$ \cos \dfrac{\pi}{6} = \dfrac{\sqrt{3}}{2} $$

$$ \tan \dfrac{\pi}{6} = \dfrac{1}{\sqrt{3}} $$

$$ \csc \dfrac{\pi}{6} = 2 $$

$$ \sec \dfrac{\pi}{6} = \dfrac{2}{\sqrt{3}} $$

$$ \cot \dfrac{\pi}{6} = \sqrt{3} $$

• $ \dfrac{\pi}{4} = 45^\circ $

$$ \sin \dfrac{\pi}{4} = \dfrac{1}{\sqrt{2}} $$

$$ \cos \dfrac{\pi}{4} = \dfrac{1}{\sqrt{2}} $$

$$ \tan \dfrac{\pi}{4} = 1 $$

$$ \csc \dfrac{\pi}{4} = \sqrt{2} $$

$$ \sec \dfrac{\pi}{4} = \sqrt{2} $$

$$ \cot \dfrac{\pi}{4} = 1 $$

• $ \dfrac{\pi}{3} = 60^\circ $

$$ \sin \dfrac{\pi}{3} = \dfrac{\sqrt{3}}{2} $$

$$ \cos \dfrac{\pi}{3} = \dfrac{1}{2} $$

$$ \tan \dfrac{\pi}{3} = \sqrt{3} $$

$$ \csc \dfrac{\pi}{3} = \dfrac{2}{\sqrt{3}} $$

$$ \sec \dfrac{\pi}{3} = 2 $$

$$ \cot \dfrac{\pi}{3} = \dfrac{1}{\sqrt{3}} $$

• $ \dfrac{\pi}{2} = 90^\circ $

$$ \sin \dfrac{\pi}{2} = 1 $$

$$ \cos \dfrac{\pi}{2} = 0 $$

$$ \tan \dfrac{\pi}{2} \text{   undefined} $$

$$ \csc \dfrac{\pi}{2} = 1 $$

$$ \sec \dfrac{\pi}{2} \text{   undefined} $$

$$ \cot \dfrac{\pi}{2} = 0 $$

• $ \pi = 180^\circ $

$$ \sin \pi = 0 $$

$$ \cos \pi = -1 $$

$$ \tan \pi = 0 $$

$$ \csc \pi \text{   undefined} $$

$$ \sec \pi = -1 $$

$$ \cot \pi \text{   undefined} $$

• $ \dfrac{3\pi}{2} = 270^\circ $

$$ \sin \dfrac{3\pi}{2} = -1 $$

$$ \cos \dfrac{3\pi}{2} = 0 $$

$$ \tan \dfrac{3\pi}{2} \text{   undefined} $$

$$ \csc \dfrac{3\pi}{2} = -1 $$

$$ \sec \dfrac{3\pi}{2} \text{   undefined} $$

$$ \cot \dfrac{3\pi}{2} = 0 $$

• $ 2\pi = 360^\circ $

$$ \sin 2\pi = 0 $$

$$ \cos 2\pi = 1 $$

$$ \tan 2\pi = 0 $$

$$ \csc 2\pi \text{   undefined} $$

$$ \sec 2\pi = 1 $$

$$ \cot 2\pi \text{   undefined} $$